We have,
(K.E.)1= P2/2m
Where ‘P’ is momentum and ‘m’ is the mass of the object.
If the momentum is doubled then,
(K.E.)2 = (2P)2/2m
Or, (K.E.)2 = 4(K.E.)1
Therefore, on doubling the momentum, the K.E. of the body increases by four times its initial K.E.
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Chemistry 11 Notes -
Chemistry 11 Notes -
Chemistry 11 Notes -
Chemistry 11 Notes -
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