Physics XI Content
11. A cork is floating in water. What is the apparent weight of the cork?
The apparent weight = wt of cork – wt of displaced liquid
In case of cork floating in the liquid, the wt of the cork is equal to the weight of the liquid displaced, i.e. wt of the cork = weight of the displaced liquid.
The apparent weight = weight of the cork – weight of displaced liquid
The apparent weight = 0