The apparent weight = wt of cork – wt of displaced liquid
In case of cork floating in the liquid, the wt of the cork is equal to the weight of the liquid displaced, i.e. wt of the cork = weight of the displaced liquid.
The apparent weight = weight of the cork – weight of displaced liquid
The apparent weight = 0
This post was part of TyroCity discussion forum
Question asked by chimini_chand
Answered by drupadh_thapa
Top comments (0)