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A cork is floating in water. What is the apparent weight of the cork?

The apparent weight = wt of cork – wt of displaced liquid

In case of cork floating in the liquid, the wt of the cork is equal to the weight of the liquid displaced, i.e. wt of the cork = weight of the displaced liquid.

The apparent weight = weight of the cork – weight of displaced liquid

The apparent weight = 0

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Question asked by chimini_chand
Answered by drupadh_thapa

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